99 lines
1.8 KiB
Plaintext
99 lines
1.8 KiB
Plaintext
{
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"cells": [
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "4f8f476d",
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"metadata": {},
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"outputs": [
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{
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"data": {
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"text/plain": [
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"(10, -1, 1)"
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]
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},
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"execution_count": 1,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"from rabin import encrypt, decrypt, encode, decode"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 17,
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"id": "402fb09a",
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"metadata": {},
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"outputs": [
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{
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"data": {
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"text/plain": [
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"81"
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]
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},
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"execution_count": 17,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"#Verschlüsseln des Buchstaben \"j\" mit (p,q) = (11,19)\n",
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"p, q = 11, 19\n",
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"clear_text = \"j\"\n",
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"\n",
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"clear = encode(clear_text)\n",
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"cipher = encrypt(clear, p, q)\n",
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"\n",
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"cipher"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 18,
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"id": "8264c687",
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"metadata": {},
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"outputs": [
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{
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"data": {
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"text/plain": [
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"('j', 'ĩ', 'Ü', '·')"
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]
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},
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"execution_count": 18,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"#Entschlüsseln unter Kenntnis des Schlüssels (p, q)\n",
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"possible_solutions = decrypt(cipher, p, q)\n",
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"\n",
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"tuple(map(decode, possible_solutions))"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.13.2"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 5
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}
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